0=7+17t-16t^2

Solution for 0=7+17t-16t^2 equation:

0=7+17t-16t^2

We move all terms to the left:

0-(7+17t-16t^2)=0

We add all the numbers together, and all the variables

-(7+17t-16t^2)=0

We get rid of parentheses

16t^2-17t-7=0

a = 16; b = -17; c = -7;
Δ = b2-4ac
Δ = -172-4·16·(-7)
Δ = 737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{737}}{2*16}=\frac{17-\sqrt{737}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{737}}{2*16}=\frac{17+\sqrt{737}}{32}
$